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Jon SQL tests Hidden field, visible test field using SQL




'Select count(*) As DefaultValue from users' into text field.

  as you can see, it does not work.

This is the example SQL provided below the SQL entry field :(

 

There is also a hidden field 'HiddenID' trying to be filled via SQL

- I can't see this field in the page source at all when I display it.

 



'select userid as QuestionOption,username AS

QuestionOptionValue from users where userid >100 and

userid < 110' is being used here.  Notice that

SQL works in this case.  But if I change the

WHERE clause to 'where userid = $(UserID)

(or any other field shortname) it is broken.


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